1/9(9t-6)=t+6/18

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Solution for 1/9(9t-6)=t+6/18 equation: 


t in (-oo:+oo)

(1/9)*(9*t-6) = t+6/18 // - t+6/18

(1/9)*(9*t-6)-t-(6/18) = 0

(1/9)*(9*t-6)-t-1/3 = 0

1/9*(9*t-6)-t-1/3 = 0

(1/9*3*(9*t-6))/3+(3*(-t))/3-1/3 = 0

1/9*3*(9*t-6)+3*(-t)-1 = 0

-2-1 = 0

-3 = 0

-3/3 = 0

-3/3 = 0 // * 3

-3 = 0

t belongs to the empty set

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