1/9(9y+18)-7=-1/8(16y-32)

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Solution for 1/9(9y+18)-7=-1/8(16y-32) equation: 



1/9(9y+18)-7=-1/8(16y-32)

We move all terms to the left:

1/9(9y+18)-7-(-1/8(16y-32))=0



Domain of the equation: 9(9y+18)!=0

y∈R





Domain of the equation: 8(16y-32))!=0

y∈R



We calculate fractions


(8y1/(9(9y+18)*8(16y-32)))+(-(-9y9)/(9(9y+18)*8(16y-32)))-7=0



We calculate terms in parentheses: +(8y1/(9(9y+18)*8(16y-32))), so:

8y1/(9(9y+18)*8(16y-32))

We multiply all the terms by the denominator


8y1

We add all the numbers together, and all the variables

8y

Back to the equation:

+(8y)





We calculate terms in parentheses: +(-(-9y9)/(9(9y+18)*8(16y-32))), so:

-(-9y9)/(9(9y+18)*8(16y-32))

We add all the numbers together, and all the variables

-(-9y^9)/(9(9y+18)*8(16y-32))

We multiply all the terms by the denominator


-(-9y^9)

We do not support eypression: y^9

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