1/9(9y+18)-8=-1/3(9y-18)

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Solution for 1/9(9y+18)-8=-1/3(9y-18) equation: 



1/9(9y+18)-8=-1/3(9y-18)

We move all terms to the left:

1/9(9y+18)-8-(-1/3(9y-18))=0



Domain of the equation: 9(9y+18)!=0

y∈R





Domain of the equation: 3(9y-18))!=0

y∈R



We calculate fractions


(3y9/(9(9y+18)*3(9y-18)))+(-(-9y9)/(9(9y+18)*3(9y-18)))-8=0



We calculate terms in parentheses: +(3y9/(9(9y+18)*3(9y-18))), so:

3y9/(9(9y+18)*3(9y-18))

We multiply all the terms by the denominator


3y9

We add all the numbers together, and all the variables

3y^9

We do not support eypression: y^9

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