1/9(9y+18)-8=-1/7(21y-42)

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Solution for 1/9(9y+18)-8=-1/7(21y-42) equation:



1/9(9y+18)-8=-1/7(21y-42)
We move all terms to the left:
1/9(9y+18)-8-(-1/7(21y-42))=0
Domain of the equation: 9(9y+18)!=0
y∈R
Domain of the equation: 7(21y-42))!=0
y∈R
We calculate fractions
(7y2/(9(9y+18)*7(21y-42)))+(-(-9y9)/(9(9y+18)*7(21y-42)))-8=0
We calculate terms in parentheses: +(7y2/(9(9y+18)*7(21y-42))), so:
7y2/(9(9y+18)*7(21y-42))
We multiply all the terms by the denominator
7y2
We add all the numbers together, and all the variables
7y^2
Back to the equation:
+(7y^2)
We calculate terms in parentheses: +(-(-9y9)/(9(9y+18)*7(21y-42))), so:
-(-9y9)/(9(9y+18)*7(21y-42))
We add all the numbers together, and all the variables
-(-9y^9)/(9(9y+18)*7(21y-42))
We multiply all the terms by the denominator
-(-9y^9)
We do not support eypression: y^9

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