1/9(9y+18)-8=1/4(12y-24)

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Solution for 1/9(9y+18)-8=1/4(12y-24) equation: 



1/9(9y+18)-8=1/4(12y-24)

We move all terms to the left:

1/9(9y+18)-8-(1/4(12y-24))=0



Domain of the equation: 9(9y+18)!=0

y∈R





Domain of the equation: 4(12y-24))!=0

y∈R



We calculate fractions


(4y1/(9(9y+18)*4(12y-24)))+(-9y9/(9(9y+18)*4(12y-24)))-8=0



We calculate terms in parentheses: +(4y1/(9(9y+18)*4(12y-24))), so:

4y1/(9(9y+18)*4(12y-24))

We multiply all the terms by the denominator


4y1

We add all the numbers together, and all the variables

4y

Back to the equation:

+(4y)





We calculate terms in parentheses: +(-9y9/(9(9y+18)*4(12y-24))), so:

-9y9/(9(9y+18)*4(12y-24))

We multiply all the terms by the denominator


-9y9

We add all the numbers together, and all the variables

-9y^9

We do not support eypression: y^9

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