1/9(9y+36)-6=-1/9(18y-63)

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Solution for 1/9(9y+36)-6=-1/9(18y-63) equation: 



1/9(9y+36)-6=-1/9(18y-63)

We move all terms to the left:

1/9(9y+36)-6-(-1/9(18y-63))=0



Domain of the equation: 9(9y+36)!=0

y∈R





Domain of the equation: 9(18y-63))!=0

y∈R



We calculate fractions


(9y1/(9(9y+36)*9(18y-63)))+(-(-9y9)/(9(9y+36)*9(18y-63)))-6=0



We calculate terms in parentheses: +(9y1/(9(9y+36)*9(18y-63))), so:

9y1/(9(9y+36)*9(18y-63))

We multiply all the terms by the denominator


9y1

We add all the numbers together, and all the variables

9y

Back to the equation:

+(9y)





We calculate terms in parentheses: +(-(-9y9)/(9(9y+36)*9(18y-63))), so:

-(-9y9)/(9(9y+36)*9(18y-63))

We add all the numbers together, and all the variables

-(-9y^9)/(9(9y+36)*9(18y-63))

We multiply all the terms by the denominator


-(-9y^9)

We do not support eypression: y^9

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