1/9(a+2)=1/3(7-a)

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Solution for 1/9(a+2)=1/3(7-a) equation: 



1/9(a+2)=1/3(7-a)

We move all terms to the left:

1/9(a+2)-(1/3(7-a))=0



Domain of the equation: 9(a+2)!=0

a∈R





Domain of the equation: 3(7-a))!=0

a∈R



We add all the numbers together, and all the variables

1/9(a+2)-(1/3(-1a+7))=0

We calculate fractions


(3a(-)/(9(a+2)*3(-1a+7)))+(-9aa/(9(a+2)*3(-1a+7)))=0



We calculate terms in parentheses: +(3a(-)/(9(a+2)*3(-1a+7))), so:

3a(-)/(9(a+2)*3(-1a+7))

We add all the numbers together, and all the variables

3a0/(9(a+2)*3(-1a+7))

We multiply all the terms by the denominator


3a0

We add all the numbers together, and all the variables

3a

Back to the equation:

+(3a)





We calculate terms in parentheses: +(-9aa/(9(a+2)*3(-1a+7))), so:

-9aa/(9(a+2)*3(-1a+7))

We multiply all the terms by the denominator


-9aa

Back to the equation:

+(-9aa)



We get rid of parentheses

3a-9aa=0

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