1/9(a+9)=1/4(8-a)

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Solution for 1/9(a+9)=1/4(8-a) equation: 



1/9(a+9)=1/4(8-a)

We move all terms to the left:

1/9(a+9)-(1/4(8-a))=0



Domain of the equation: 9(a+9)!=0

a∈R





Domain of the equation: 4(8-a))!=0

a∈R



We add all the numbers together, and all the variables

1/9(a+9)-(1/4(-1a+8))=0

We calculate fractions


(4a(-)/(9(a+9)*4(-1a+8)))+(-9aa/(9(a+9)*4(-1a+8)))=0



We calculate terms in parentheses: +(4a(-)/(9(a+9)*4(-1a+8))), so:

4a(-)/(9(a+9)*4(-1a+8))

We add all the numbers together, and all the variables

4a0/(9(a+9)*4(-1a+8))

We multiply all the terms by the denominator


4a0

We add all the numbers together, and all the variables

4a

Back to the equation:

+(4a)





We calculate terms in parentheses: +(-9aa/(9(a+9)*4(-1a+8))), so:

-9aa/(9(a+9)*4(-1a+8))

We multiply all the terms by the denominator


-9aa

Back to the equation:

+(-9aa)



We get rid of parentheses

4a-9aa=0

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