1/9(t-4)=-3

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Solution for 1/9(t-4)=-3 equation: 



1/9(t-4)=-3

We move all terms to the left:

1/9(t-4)-(-3)=0



Domain of the equation: 9(t-4)!=0

t∈R



We add all the numbers together, and all the variables

1/9(t-4)+3=0

We multiply all the terms by the denominator


3*9(t-4)+1=0

Wy multiply elements

27t(t+1=0

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