1/9(x+27)-1/3(x-3)=x+5

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Solution for 1/9(x+27)-1/3(x-3)=x+5 equation: 



1/9(x+27)-1/3(x-3)=x+5

We move all terms to the left:

1/9(x+27)-1/3(x-3)-(x+5)=0



Domain of the equation: 9(x+27)!=0

x∈R





Domain of the equation: 3(x-3)!=0

x∈R



We get rid of parentheses

1/9(x+27)-1/3(x-3)-x-5=0

We calculate fractions


-x+(3xx/(9(x+27)*3(x-3))+(-9xx/(9(x+27)*3(x-3))-5=0

We can not solve this equation

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