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1/9(x+27)-1/3(x-3)=x-17
We move all terms to the left:
1/9(x+27)-1/3(x-3)-(x-17)=0
Domain of the equation: 9(x+27)!=0
x∈R
Domain of the equation: 3(x-3)!=0We get rid of parentheses
x∈R
1/9(x+27)-1/3(x-3)-x+17=0
We calculate fractions
-x+(3xx/(9(x+27)*3(x-3))+(-9xx/(9(x+27)*3(x-3))+17=0
We can not solve this equation
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