1/9(x+9)=1/27(3x+27)

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Solution for 1/9(x+9)=1/27(3x+27) equation: 


x in (-oo:+oo)

(1/9)*(x+9) = (1/27)*(3*x+27) // - (1/27)*(3*x+27)

(1/9)*(x+9)-((1/27)*(3*x+27)) = 0

(1/9)*(x+9)+(-1/27)*(3*x+27) = 0

1/9*(x+9)-1/27*(3*x+27) = 0

1/9*(x+9)-1/27*(3*x+27) = 0

0 = 0

0 = 0

x belongs to the empty set

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