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1/9(x-18)+1/3(2x+3)=x-3
We move all terms to the left:
1/9(x-18)+1/3(2x+3)-(x-3)=0
Domain of the equation: 9(x-18)!=0
x∈R
Domain of the equation: 3(2x+3)!=0We get rid of parentheses
x∈R
1/9(x-18)+1/3(2x+3)-x+3=0
We calculate fractions
-x+(3x2/(9(x-18)*3(2x+3))+(9xx/(9(x-18)*3(2x+3))+3=0
We can not solve this equation
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