1/9(y+18)+1/3(2y+3)=y+3

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Solution for 1/9(y+18)+1/3(2y+3)=y+3 equation: 


y in (-oo:+oo)

(1/9)*(y+18)+(1/3)*(2*y+3) = y+3 // - y+3

(1/9)*(y+18)+(1/3)*(2*y+3)-y-3 = 0

1/9*(y+18)+1/3*(2*y+3)-y-3 = 0

1/9*(y+18)+1/3*(2*y+3)-y-3 = 0

7/9*y-y-3+3 = 0

3-2/9*y-3 = 0

-2/9*y = 0

(-2*y)/9 = 0

(-2*y)/9 = 0 // * 9

-2*y = 0

-2*y = 0 // : -2

y = 0

y = 0

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