1/9(y+18)-1/3(2y+3)=y+3

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Solution for 1/9(y+18)-1/3(2y+3)=y+3 equation: 


y in (-oo:+oo)

(1/9)*(y+18)-((1/3)*(2*y+3)) = y+3 // - y+3

(1/9)*(y+18)-((1/3)*(2*y+3))-y-3 = 0

(1/9)*(y+18)+(-1/3)*(2*y+3)-y-3 = 0

1/9*(y+18)-1/3*(2*y+3)-y-3 = 0

1/9*(y+18)-1/3*(2*y+3)-y-3 = 0

1-5/9*y-y-3 = 0

1-14/9*y-3 = 0

-14/9*y-2 = 0

-14/9*y-2 = 0

-14/9*y-2 = 0 // + 2

-14/9*y = 2 // : -14/9

y = 2/(-14/9)

y = -9/7

y = -9/7

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