1/9+2(t/18+4)=10

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Solution for 1/9+2(t/18+4)=10 equation: 



1/9+2(t/18+4)=10

We move all terms to the left:

1/9+2(t/18+4)-(10)=0

determiningTheFunctionDomain
2(t/18+4)-10+1/9=0

We multiply parentheses

2t+8-10+1/9=0

We multiply all the terms by the denominator


2t*9+1+8*9-10*9=0

We add all the numbers together, and all the variables

2t*9-17=0

Wy multiply elements

18t-17=0

We move all terms containing t to the left, all other terms to the right

18t=17

t=17/18

t=17/18

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