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1/9x+20.5+25.5=x
We move all terms to the left:
1/9x+20.5+25.5-(x)=0
Domain of the equation: 9x!=0We add all the numbers together, and all the variables
x!=0/9
x!=0
x∈R
-1x+1/9x+46=0
We multiply all the terms by the denominator
-1x*9x+46*9x+1=0
Wy multiply elements
-9x^2+414x+1=0
a = -9; b = 414; c = +1;
Δ = b2-4ac
Δ = 4142-4·(-9)·1
Δ = 171432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{171432}=\sqrt{36*4762}=\sqrt{36}*\sqrt{4762}=6\sqrt{4762}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(414)-6\sqrt{4762}}{2*-9}=\frac{-414-6\sqrt{4762}}{-18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(414)+6\sqrt{4762}}{2*-9}=\frac{-414+6\sqrt{4762}}{-18} $
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