1/9y-42/3=15

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Solution for 1/9y-42/3=15 equation: 



1/9y-42/3=15

We move all terms to the left:

1/9y-42/3-(15)=0



Domain of the equation: 9y!=0

y!=0/9

y!=0

y∈R



determiningTheFunctionDomain
1/9y-15-42/3=0

We add all the numbers together, and all the variables

1/9y-29=0

We multiply all the terms by the denominator


-29*9y+1=0

Wy multiply elements

-261y+1=0

We move all terms containing y to the left, all other terms to the right

-261y=-1

y=-1/-261

y=1/261

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