1/a-5/3a=1/3

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Solution for 1/a-5/3a=1/3 equation:


D( a )

a = 0

a = 0

a = 0

a in (-oo:0) U (0:+oo)

1/a-((5/3)*a) = 1/3 // - 1/3

1/a-((5/3)*a)-(1/3) = 0

(-5/3)*a+1/a-1/3 = 0

1*a^-1-5/3*a^1-1/3*a^0 = 0

(1*a^0-5/3*a^2-1/3*a^1)/(a^1) = 0 // * a^2

a^1*(1*a^0-5/3*a^2-1/3*a^1) = 0

a^1

(-5/3)*a^2+(-1/3)*a+1 = 0

(-5/3)*a^2+(-1/3)*a+1 = 0

DELTA = (-1/3)^2-(1*4*(-5/3))

DELTA = 61/9

DELTA > 0

a = ((61/9)^(1/2)-(-1/3))/(2*(-5/3)) or a = (-(-1/3)-(61/9)^(1/2))/(2*(-5/3))

a = -3/10*((61/9)^(1/2)+1/3) or a = -3/10*(1/3-(61/9)^(1/2))

a in { -3/10*((61/9)^(1/2)+1/3), -3/10*(1/3-(61/9)^(1/2))}

a in { -3/10*((61/9)^(1/2)+1/3), -3/10*(1/3-(61/9)^(1/2)) }

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