1/b(2b-10)=17

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Solution for 1/b(2b-10)=17 equation: 



1/b(2b-10)=17

We move all terms to the left:

1/b(2b-10)-(17)=0



Domain of the equation: b(2b-10)!=0

b∈R



We multiply all the terms by the denominator


-17*b(2b-10)+1=0

Wy multiply elements

-17b(2+1=0

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