1/b+1/b+7=b+8/b+7

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Solution for 1/b+1/b+7=b+8/b+7 equation: 


D( b )

b = 0

b = 0

b = 0

b in (-oo:0) U (0:+oo)

1/b+1/b+7 = b+8/b+7 // - b+8/b+7

1/b-b+1/b-(8/b)-7+7 = 0

1/b-b+1/b-8*b^-1-7+7 = 0

-1*b^1-6*b^-1 = 0

(-1*b^2-6*b^0)/(b^1) = 0 // * b^2

b^1*(-1*b^2-6*b^0) = 0

b^1

-b^2-6 = 0

-b^2-6 = 0

DELTA = 0^2-(-6*(-1)*4)

DELTA = -24

DELTA < 0

b in { } 

b belongs to the empty set

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