1/b+4=10+1/b,b+0

Solution for 1/b+4=10+1/b,b+0 equation:

1/b+4=10+1/b.b+0

We move all terms to the left:

1/b+4-(10+1/b.b+0)=0


Domain of the equation: b!=0

b∈R



Domain of the equation: b.b+0)!=0

b∈R


We add all the numbers together, and all the variables

1/b-(1/b.b+10)+4=0

We get rid of parentheses

1/b-1/b.b-10+4=0

We calculate fractions


b/b^2+(-b)/b^2-10+4=0

We add all the numbers together, and all the variables

b/b^2+(-1b)/b^2-10+4=0

We add all the numbers together, and all the variables

b/b^2+(-1b)/b^2-6=0

We multiply all the terms by the denominator


b+(-1b)-6*b^2=0

We add all the numbers together, and all the variables

-6b^2+b+(-1b)=0

We get rid of parentheses

-6b^2+b-1b=0

We add all the numbers together, and all the variables

-6b^2=0

a = -6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-6)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{0}{-12}=0$