1/b-3=1/4b

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Solution for 1/b-3=1/4b equation: 


D( b )

b = 0

b = 0

b = 0

b in (-oo:0) U (0:+oo)

1/b-3 = (1/4)*b // - (1/4)*b

1/b-((1/4)*b)-3 = 0

(-1/4)*b+1/b-3 = 0

1*b^-1-1/4*b^1-3*b^0 = 0

(1*b^0-1/4*b^2-3*b^1)/(b^1) = 0 // * b^2

b^1*(1*b^0-1/4*b^2-3*b^1) = 0

b^1

(-1/4)*b^2-3*b+1 = 0

(-1/4)*b^2-3*b+1 = 0

DELTA = (-3)^2-(1*4*(-1/4))

DELTA = 10

DELTA > 0

b = (10^(1/2)+3)/(2*(-1/4)) or b = (3-10^(1/2))/(2*(-1/4))

b = -2*(10^(1/2)+3) or b = -2*(3-10^(1/2))

b in { -2*(10^(1/2)+3), -2*(3-10^(1/2))} 

b in { -2*(10^(1/2)+3), -2*(3-10^(1/2)) }

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