1/b=-3/b+2

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Solution for 1/b=-3/b+2 equation: 


D( b )

b = 0

b = 0

b = 0

b in (-oo:0) U (0:+oo)

1/b = 2-3/b // - 2-3/b

1/b-(-3/b)-2 = 0

1/b+3*b^-1-2 = 0

4*b^-1 = 2 // : 4

b^-1 = 1/2

-1 < 0

1/(b^1) = 1/2 // * b^1

1 = 1/2*b^1 // : 1/2

2 = b^1

b = 2

b = 2

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