1/m+1/2m=1/6

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Solution for 1/m+1/2m=1/6 equation: 


D( m )

m = 0

m = 0

m = 0

m in (-oo:0) U (0:+oo)

(1/2)*m+1/m = 1/6 // - 1/6

(1/2)*m+1/m-(1/6) = 0

(1/2)*m+1/m-1/6 = 0

1/2*m^1+1*m^-1-1/6*m^0 = 0

(1/2*m^2-1/6*m^1+1*m^0)/(m^1) = 0 // * m^2

m^1*(1/2*m^2-1/6*m^1+1*m^0) = 0

m^1

(1/2)*m^2+(-1/6)*m+1 = 0

(1/2)*m^2+(-1/6)*m+1 = 0

DELTA = (-1/6)^2-(1*4*(1/2))

DELTA = -71/36

DELTA < 0

m in { } 

m belongs to the empty set

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