1/m-4(m+4)m=8

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Solution for 1/m-4(m+4)m=8 equation: 



1/m-4(m+4)m=8

We move all terms to the left:

1/m-4(m+4)m-(8)=0



Domain of the equation: m!=0

m∈R



We multiply parentheses

-4m^2+1/m-16m-8=0

We multiply all the terms by the denominator


-4m^2*m-16m*m-8*m+1=0

We add all the numbers together, and all the variables

-4m^2*m-8m-16m*m+1=0

Wy multiply elements

-4m^3-16m^2-8m+1=0

We do not support empression: m^3

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