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1/n+1/n+1=-1/n(n+1)
We move all terms to the left:
1/n+1/n+1-(-1/n(n+1))=0
Domain of the equation: n!=0
n∈R
Domain of the equation: n(n+1))!=0We calculate fractions
n∈R
(nn/(n^2n+(-(-1*n)/(n^2n+1=0
We can not solve this equation
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