1/n+2/(n+1)=2

Solution for 1/n+2/(n+1)=2 equation:

1/n+2/(n+1)=2

We move all terms to the left:

1/n+2/(n+1)-(2)=0


Domain of the equation: n!=0

n∈R



Domain of the equation: (n+1)!=0

We move all terms containing n to the left, all other terms to the right

n!=-1

n∈R


We calculate fractions


(1*(n+1))/(n^2+n)+2n/(n^2+n)-2=0


We calculate terms in parentheses: +(1*(n+1))/(n^2+n), so:

1*(n+1))/(n^2+n

We add all the numbers together, and all the variables

n+1*(n+1))/(n^2

We multiply all the terms by the denominator


n*(n^2+1*(n+1))

Back to the equation:

+(n*(n^2+1*(n+1)))


We multiply all the terms by the denominator


((n*(n^2+1*(n+1))))*(n^2+n)+2n-2*(n^2+n)=0


We calculate terms in parentheses: +((n*(n^2+1*(n+1))))*(n^2+n), so:

(n*(n^2+1*(n+1))))*(n^2+n

We add all the numbers together, and all the variables

n+(n*(n^2+1*(n+1))))*(n^2

Back to the equation:

+(n+(n*(n^2+1*(n+1))))*(n^2)


We add all the numbers together, and all the variables

2n+(n+(n*(n^2+1*(n+1))))*n^2-2*(n^2+n)=0

We multiply parentheses

-2n^2+2n+(n+(n*(n^2+1*(n+1))))*n^2-2n=0

We add all the numbers together, and all the variables

-2n^2+(n+(n*(n^2+1*(n+1))))*n^2=0