1/n=1/5n-n-1/5n

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Solution for 1/n=1/5n-n-1/5n equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

1/n = (1/5)*n-n-((1/5)*n) // - (1/5)*n-n-((1/5)*n)

n-((1/5)*n)+(1/5)*n+1/n = 0

(-1/5)*n+n+(1/5)*n+1/n = 0

1*n^1+1*n^-1 = 0

(1*n^2+1*n^0)/(n^1) = 0 // * n^2

n^1*(1*n^2+1*n^0) = 0

n^1

n^2+1 = 0

n^2+1 = 0

DELTA = 0^2-(1*1*4)

DELTA = -4

DELTA < 0

n in { } 

n belongs to the empty set

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