1/t+1/3t=1/2

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Solution for 1/t+1/3t=1/2 equation: 


D( t )

t = 0

t = 0

t = 0

t in (-oo:0) U (0:+oo)

(1/3)*t+1/t = 1/2 // - 1/2

(1/3)*t+1/t-(1/2) = 0

(1/3)*t+1/t-1/2 = 0

1/3*t^1+1*t^-1-1/2*t^0 = 0

(1/3*t^2-1/2*t^1+1*t^0)/(t^1) = 0 // * t^2

t^1*(1/3*t^2-1/2*t^1+1*t^0) = 0

t^1

(1/3)*t^2+(-1/2)*t+1 = 0

(1/3)*t^2+(-1/2)*t+1 = 0

DELTA = (-1/2)^2-(1*4*(1/3))

DELTA = -13/12

DELTA < 0

t in { } 

t belongs to the empty set

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