1/t-1/2t-1/5t=10/t+1

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Solution for 1/t-1/2t-1/5t=10/t+1 equation: 


D( t )

t = 0

t = 0

t = 0

t in (-oo:0) U (0:+oo)

1/t-((1/2)*t)-((1/5)*t) = 10/t+1 // - 10/t+1

1/t-((1/2)*t)-((1/5)*t)-(10/t)-1 = 0

(-1/2)*t+(-1/5)*t+1/t-10*t^-1-1 = 0

-7/10*t^1-9*t^-1-1*t^0 = 0

(-7/10*t^2-1*t^1-9*t^0)/(t^1) = 0 // * t^2

t^1*(-7/10*t^2-1*t^1-9*t^0) = 0

t^1

(-7/10)*t^2-t-9 = 0

(-7/10)*t^2-t-9 = 0

DELTA = (-1)^2-(-9*4*(-7/10))

DELTA = -121/5

DELTA < 0

t in { } 

t belongs to the empty set

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