1/w+5=w-3/w-1/w

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Solution for 1/w+5=w-3/w-1/w equation: 


D( w )

w = 0

w = 0

w = 0

w in (-oo:0) U (0:+oo)

1/w+5 = w-(3/w)-(1/w) // - w-(3/w)-(1/w)

1/w-w+3/w+1/w+5 = 0

5*w^-1-1*w^1+5*w^0 = 0

(5*w^1-1*w^2+5*w^0)/(w^1) = 0 // * w^2

w^1*(5*w^1-1*w^2+5*w^0) = 0

w^1

5*w-w^2+5 = 0

5*w-w^2+5 = 0

DELTA = 5^2-(-1*4*5)

DELTA = 45

DELTA > 0

w = (45^(1/2)-5)/(-1*2) or w = (-45^(1/2)-5)/(-1*2)

w = (3*5^(1/2)-5)/(-2) or w = (-3*5^(1/2)-5)/(-2)

w in { (3*5^(1/2)-5)/(-2), (-3*5^(1/2)-5)/(-2)} 

w in { (3*5^(1/2)-5)/(-2), (-3*5^(1/2)-5)/(-2) }

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