1/w-1-1/5w-5=4/5w-5

Solution for 1/w-1-1/5w-5=4/5w-5 equation:

D( w )

w = 0

w = 0

w = 0

w in (-oo:0) U (0:+oo)

1/w-((1/5)*w)-5-1 = (4/5)*w-5 // - (4/5)*w-5

1/w-((1/5)*w)-((4/5)*w)-5-1+5 = 0

(-1/5)*w+(-4/5)*w+1/w-5-1+5 = 0

1*w^-1-1*w^1-1*w^0 = 0

(1*w^0-1*w^2-1*w^1)/(w^1) = 0 // * w^2

w^1*(1*w^0-1*w^2-1*w^1) = 0

w^1

1-w^2-w = 0

1-w^2-w = 0

DELTA = (-1)^2-(-1*1*4)

DELTA = 5

DELTA > 0

w = (5^(1/2)+1)/(-1*2) or w = (1-5^(1/2))/(-1*2)

w = (5^(1/2)+1)/(-2) or w = (1-5^(1/2))/(-2)

w in { (5^(1/2)+1)/(-2), (1-5^(1/2))/(-2)} 

w in { (5^(1/2)+1)/(-2), (1-5^(1/2))/(-2) }