1/w-1-3/4w-w=1/4w-4

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Solution for 1/w-1-3/4w-w=1/4w-4 equation: 


D( w )

w = 0

w = 0

w = 0

w in (-oo:0) U (0:+oo)

1/w-((3/4)*w)-w-1 = (1/4)*w-4 // - (1/4)*w-4

1/w-((3/4)*w)-w-((1/4)*w)-1+4 = 0

(-3/4)*w-w+(-1/4)*w+1/w-1+4 = 0

1*w^-1-2*w^1+3*w^0 = 0

(3*w^1-2*w^2+1*w^0)/(w^1) = 0 // * w^2

w^1*(3*w^1-2*w^2+1*w^0) = 0

w^1

3*w-2*w^2+1 = 0

3*w-2*w^2+1 = 0

DELTA = 3^2-(-2*1*4)

DELTA = 17

DELTA > 0

w = (17^(1/2)-3)/(-2*2) or w = (-17^(1/2)-3)/(-2*2)

w = (17^(1/2)-3)/(-4) or w = (17^(1/2)+3)/4

w in { (17^(1/2)-3)/(-4), (17^(1/2)+3)/4} 

w in { (17^(1/2)-3)/(-4), (17^(1/2)+3)/4 }

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