1/w-2-2/5w-10=3/5w-10

Solution for 1/w-2-2/5w-10=3/5w-10 equation:

D( w )

w = 0

w = 0

w = 0

w in (-oo:0) U (0:+oo)

1/w-((2/5)*w)-10-2 = (3/5)*w-10 // - (3/5)*w-10

1/w-((2/5)*w)-((3/5)*w)-10-2+10 = 0

(-2/5)*w+(-3/5)*w+1/w-10-2+10 = 0

1*w^-1-1*w^1-2*w^0 = 0

(1*w^0-1*w^2-2*w^1)/(w^1) = 0 // * w^2

w^1*(1*w^0-1*w^2-2*w^1) = 0

w^1

1-w^2-2*w = 0

1-w^2-2*w = 0

DELTA = (-2)^2-(-1*1*4)

DELTA = 8

DELTA > 0

w = (8^(1/2)+2)/(-1*2) or w = (2-8^(1/2))/(-1*2)

w = (2*2^(1/2)+2)/(-2) or w = (2-2*2^(1/2))/(-2)

w in { (2*2^(1/2)+2)/(-2), (2-2*2^(1/2))/(-2)} 

w in { (2*2^(1/2)+2)/(-2), (2-2*2^(1/2))/(-2) }