1/w-3-3/4w-12=1/4w-12

Solution for 1/w-3-3/4w-12=1/4w-12 equation:

D( w )

w = 0

w = 0

w = 0

w in (-oo:0) U (0:+oo)

1/w-((3/4)*w)-12-3 = (1/4)*w-12 // - (1/4)*w-12

1/w-((3/4)*w)-((1/4)*w)-12-3+12 = 0

(-3/4)*w+(-1/4)*w+1/w-12-3+12 = 0

1*w^-1-1*w^1-3*w^0 = 0

(1*w^0-1*w^2-3*w^1)/(w^1) = 0 // * w^2

w^1*(1*w^0-1*w^2-3*w^1) = 0

w^1

1-w^2-3*w = 0

1-w^2-3*w = 0

DELTA = (-3)^2-(-1*1*4)

DELTA = 13

DELTA > 0

w = (13^(1/2)+3)/(-1*2) or w = (3-13^(1/2))/(-1*2)

w = (13^(1/2)+3)/(-2) or w = (3-13^(1/2))/(-2)

w in { (13^(1/2)+3)/(-2), (3-13^(1/2))/(-2)} 

w in { (13^(1/2)+3)/(-2), (3-13^(1/2))/(-2) }