1/x+(x-3)=x-4

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Solution for 1/x+(x-3)=x-4 equation: 



1/x+(x-3)=x-4

We move all terms to the left:

1/x+(x-3)-(x-4)=0



Domain of the equation: x!=0

x∈R



We get rid of parentheses

1/x+x-x-3+4=0

We multiply all the terms by the denominator


x*x-x*x-3*x+4*x+1=0

We add all the numbers together, and all the variables

x+x*x-x*x+1=0

Wy multiply elements

x^2-1x^2+x+1=0

We add all the numbers together, and all the variables

x+1=0

We move all terms containing x to the left, all other terms to the right

x=-1

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