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1/x+1(+4)=13/x+1
We move all terms to the left:
1/x+1(+4)-(13/x+1)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: x+1)!=0We add all the numbers together, and all the variables
x∈R
1/x-(13/x+1)+14=0
We get rid of parentheses
1/x-13/x-1+14=0
We multiply all the terms by the denominator
-1*x+14*x+1-13=0
We add all the numbers together, and all the variables
13x-12=0
We move all terms containing x to the left, all other terms to the right
13x=12
x=12/13
x=12/13
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