1/x+1/(x+1)=7/12

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Solution for 1/x+1/(x+1)=7/12 equation:


D( x )

x = 0

x+1 = 0

x = 0

x = 0

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:0) U (0:+oo)

1/(x+1)+1/x = 7/12 // - 7/12

1/(x+1)+1/x-(7/12) = 0

1/(x+1)+1/x-7/12 = 0

(1*12*x)/(12*x*(x+1))+(1*12*(x+1))/(12*x*(x+1))+(-7*x*(x+1))/(12*x*(x+1)) = 0

1*12*(x+1)-7*x*(x+1)+1*12*x = 0

24*x-7*x^2-7*x+12 = 0

17*x-7*x^2+12 = 0

17*x-7*x^2+12 = 0

17*x-7*x^2+12 = 0

DELTA = 17^2-(-7*4*12)

DELTA = 625

DELTA > 0

x = (625^(1/2)-17)/(-7*2) or x = (-625^(1/2)-17)/(-7*2)

x = -4/7 or x = 3

(x+4/7)*(x-3) = 0

((x+4/7)*(x-3))/(12*x*(x+1)) = 0

((x+4/7)*(x-3))/(12*x*(x+1)) = 0 // * 12*x*(x+1)

(x+4/7)*(x-3) = 0

( x+4/7 )

x+4/7 = 0 // - 4/7

x = -4/7

( x-3 )

x-3 = 0 // + 3

x = 3

x in { -4/7, 3 }

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