1/x+1/(x+2)=1/5

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Solution for 1/x+1/(x+2)=1/5 equation: 



1/x+1/(x+2)=1/5

We move all terms to the left:

1/x+1/(x+2)-(1/5)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: (x+2)!=0

We move all terms containing x to the left, all other terms to the right

x!=-2

x∈R



We add all the numbers together, and all the variables

1/x+1/(x+2)-(+1/5)=0

We get rid of parentheses

1/x+1/(x+2)-1/5=0

We calculate fractions


(-1x^2*()/(5x^2+10x)+(5x+10)/(5x^2+10x)+25x/(5x^2+10x)=0



We calculate terms in parentheses: +(-1x^2*()/(5x^2+10x)+(5x+10)/(5x^2+10x)+25x/(5x^2+10x), so:

-1x^2*()/(5x^2+10x)+(5x+10)/(5x^2+10x)+25x/(5x^2+10x

We calculate fractions

We do not support expression: x^3

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