1/x+1/(x+3)=7/10

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Solution for 1/x+1/(x+3)=7/10 equation: 



1/x+1/(x+3)=7/10

We move all terms to the left:

1/x+1/(x+3)-(7/10)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: (x+3)!=0

We move all terms containing x to the left, all other terms to the right

x!=-3

x∈R



We add all the numbers together, and all the variables

1/x+1/(x+3)-(+7/10)=0

We get rid of parentheses

1/x+1/(x+3)-7/10=0

We calculate fractions


(-7x^2*()/(10x^2+30x)+(10x+30)/(10x^2+30x)+10x/(10x^2+30x)=0



We calculate terms in parentheses: +(-7x^2*()/(10x^2+30x)+(10x+30)/(10x^2+30x)+10x/(10x^2+30x), so:

-7x^2*()/(10x^2+30x)+(10x+30)/(10x^2+30x)+10x/(10x^2+30x

We calculate fractions

We do not support expression: x^3

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