1/x+1/(x+4)=1/2

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Solution for 1/x+1/(x+4)=1/2 equation:



1/x+1/(x+4)=1/2
We move all terms to the left:
1/x+1/(x+4)-(1/2)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: (x+4)!=0
We move all terms containing x to the left, all other terms to the right
x!=-4
x∈R
We add all the numbers together, and all the variables
1/x+1/(x+4)-(+1/2)=0
We get rid of parentheses
1/x+1/(x+4)-1/2=0
We calculate fractions
(-1x^2*()/(2x^2+8x)+(2x+8)/(2x^2+8x)+4x/(2x^2+8x)=0
We calculate terms in parentheses: +(-1x^2*()/(2x^2+8x)+(2x+8)/(2x^2+8x)+4x/(2x^2+8x), so:
-1x^2*()/(2x^2+8x)+(2x+8)/(2x^2+8x)+4x/(2x^2+8x
We calculate fractions
We do not support expression: x^3

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