1/x+1/(x+4)=1/3

Solution for 1/x+1/(x+4)=1/3 equation:

1/x+1/(x+4)=1/3

We move all terms to the left:

1/x+1/(x+4)-(1/3)=0


Domain of the equation: x!=0

x∈R



Domain of the equation: (x+4)!=0

We move all terms containing x to the left, all other terms to the right

x!=-4

x∈R


We add all the numbers together, and all the variables

1/x+1/(x+4)-(+1/3)=0

We get rid of parentheses

1/x+1/(x+4)-1/3=0

We calculate fractions


(-1x^2*()/(3x^2+12x)+(3x+12)/(3x^2+12x)+9x/(3x^2+12x)=0


We calculate terms in parentheses: +(-1x^2*()/(3x^2+12x)+(3x+12)/(3x^2+12x)+9x/(3x^2+12x), so:

-1x^2*()/(3x^2+12x)+(3x+12)/(3x^2+12x)+9x/(3x^2+12x

We calculate fractions

We do not support expression: x^3