1/x+1/2x+1/3x=1

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Solution for 1/x+1/2x+1/3x=1 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(1/2)*x+(1/3)*x+1/x = 1 // - 1

(1/2)*x+(1/3)*x+1/x-1 = 0

5/6*x^1+1*x^-1-1*x^0 = 0

(5/6*x^2-1*x^1+1*x^0)/(x^1) = 0 // * x^2

x^1*(5/6*x^2-1*x^1+1*x^0) = 0

x^1

(5/6)*x^2-x+1 = 0

(5/6)*x^2-x+1 = 0

DELTA = (-1)^2-(1*4*(5/6))

DELTA = -7/3

DELTA < 0

x in { } 

x belongs to the empty set

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