1/x+1/2x+1/3x=18

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Solution for 1/x+1/2x+1/3x=18 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(1/2)*x+(1/3)*x+1/x = 18 // - 18

(1/2)*x+(1/3)*x+1/x-18 = 0

5/6*x^1+1*x^-1-18*x^0 = 0

(5/6*x^2-18*x^1+1*x^0)/(x^1) = 0 // * x^2

x^1*(5/6*x^2-18*x^1+1*x^0) = 0

x^1

(5/6)*x^2-18*x+1 = 0

(5/6)*x^2-18*x+1 = 0

DELTA = (-18)^2-(1*4*(5/6))

DELTA = 962/3

DELTA > 0

x = ((962/3)^(1/2)+18)/(2*(5/6)) or x = (18-(962/3)^(1/2))/(2*(5/6))

x = 3/5*((962/3)^(1/2)+18) or x = 3/5*(18-(962/3)^(1/2))

x in { 3/5*(18-(962/3)^(1/2)), 3/5*((962/3)^(1/2)+18)}

x in { 3/5*(18-(962/3)^(1/2)), 3/5*((962/3)^(1/2)+18) }

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