1/x+1/2x=1/18

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Solution for 1/x+1/2x=1/18 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(1/2)*x+1/x = 1/18 // - 1/18

(1/2)*x+1/x-(1/18) = 0

(1/2)*x+1/x-1/18 = 0

1/2*x^1+1*x^-1-1/18*x^0 = 0

(1/2*x^2-1/18*x^1+1*x^0)/(x^1) = 0 // * x^2

x^1*(1/2*x^2-1/18*x^1+1*x^0) = 0

x^1

(1/2)*x^2+(-1/18)*x+1 = 0

(1/2)*x^2+(-1/18)*x+1 = 0

DELTA = (-1/18)^2-(1*4*(1/2))

DELTA = -647/324

DELTA < 0

x in { } 

x belongs to the empty set

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