1/x+1/3x=1/6

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Solution for 1/x+1/3x=1/6 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(1/3)*x+1/x = 1/6 // - 1/6

(1/3)*x+1/x-(1/6) = 0

(1/3)*x+1/x-1/6 = 0

1/3*x^1+1*x^-1-1/6*x^0 = 0

(1/3*x^2-1/6*x^1+1*x^0)/(x^1) = 0 // * x^2

x^1*(1/3*x^2-1/6*x^1+1*x^0) = 0

x^1

(1/3)*x^2+(-1/6)*x+1 = 0

(1/3)*x^2+(-1/6)*x+1 = 0

DELTA = (-1/6)^2-(1*4*(1/3))

DELTA = -47/36

DELTA < 0

x in { } 

x belongs to the empty set

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