1/x+1/5x=6/25

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Solution for 1/x+1/5x=6/25 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(1/5)*x+1/x = 6/25 // - 6/25

(1/5)*x+1/x-(6/25) = 0

(1/5)*x+1/x-6/25 = 0

1/5*x^1+1*x^-1-6/25*x^0 = 0

(1/5*x^2-6/25*x^1+1*x^0)/(x^1) = 0 // * x^2

x^1*(1/5*x^2-6/25*x^1+1*x^0) = 0

x^1

(1/5)*x^2+(-6/25)*x+1 = 0

(1/5)*x^2+(-6/25)*x+1 = 0

DELTA = (-6/25)^2-(1*4*(1/5))

DELTA = -464/625

DELTA < 0

x in { } 

x belongs to the empty set

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