1/x+1/x+3=x+4/x+3

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Solution for 1/x+1/x+3=x+4/x+3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x+1/x+3 = x+4/x+3 // - x+4/x+3

1/x-x+1/x-(4/x)-3+3 = 0

1/x-x+1/x-4*x^-1-3+3 = 0

-1*x^1-2*x^-1 = 0

(-1*x^2-2*x^0)/(x^1) = 0 // * x^2

x^1*(-1*x^2-2*x^0) = 0

x^1

-x^2-2 = 0

-x^2-2 = 0

DELTA = 0^2-(-2*(-1)*4)

DELTA = -8

DELTA < 0

x in { } 

x belongs to the empty set

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