1/x+1/x-4=9/4x-8

Solution for 1/x+1/x-4=9/4x-8 equation:

1/x+1/x-4=9/4x-8

We move all terms to the left:

1/x+1/x-4-(9/4x-8)=0


Domain of the equation: x!=0

x∈R



Domain of the equation: 4x-8)!=0

x∈R


We get rid of parentheses

1/x+1/x-9/4x+8-4=0

We calculate fractions


(4x+1)/4x^2+(-9x)/4x^2+8-4=0

We add all the numbers together, and all the variables

(4x+1)/4x^2+(-9x)/4x^2+4=0

We multiply all the terms by the denominator


(4x+1)+(-9x)+4*4x^2=0

Wy multiply elements

16x^2+(4x+1)+(-9x)=0

We get rid of parentheses

16x^2+4x-9x+1=0

We add all the numbers together, and all the variables

16x^2-5x+1=0

a = 16; b = -5; c = +1;
Δ = b2-4ac
Δ = -52-4·16·1
Δ = -39
Delta is less than zero, so there is no solution for the equation